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Q: What is the product of the prime factors of 235?

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As a product of its prime factors: 5 times 47 = 235

5 x 47 = 235

235 is a composite number because it has factors other than 1 and itself.The 4 factors of 235 are 1, 5, 47 and 235.The factor pairs of 235 are 1 * 235 and 5 * 47.The proper factors of 235 are 1, 5, and 47 or,if the definition you are using excludes 1, they are 5 and 47.The prime factors of 235 are 5 and 47.The distinct prime factors of 235 are also 5 and 47 since there is no repetition of factors.The prime factorization of 235 is: 235 = 5 * 47 .

The prime factors of 18 are 2, 3, and 3. The product of these prime factors is 18.The distinct prime factors of 18 are 2 and 3. The product of these distinct prime factors is 6.

The product of factors is called the product.The product of prime factors is called the prime factorization.

Multiply prime numbers or prime factors to find their product.

37 is already prime. There is no product of prime factors for prime numbers.

The product of the prime factors of any number is equal to the number itself. Therefore, the product of the prime factors of 350 is 350.

The product of the prime factors of 42 is 42.

The prime factorization of a number is writing it as a product of its prime factors.

It is simply the whole number written as the product of its prime factors.It is simply the whole number written as the product of its prime factors.It is simply the whole number written as the product of its prime factors.It is simply the whole number written as the product of its prime factors.

The product of the prime factors of a number is the number itself.

As a product of its prime factors: 225*5 = 100

The prime factorization of a number is writing it as a product of its prime factors.

35 as the product of its prime factors is = 5 x 7

As a product of its prime factors: 2*2*2*5 = 40 As a product of its prime factors: 2*2*2*7 = 56 As a product of its prime factors: 3*13 = 39

As a product of its prime factors in exponents: 24*5 = 80

215 as the product of prime factors can be represented as 215 = 5x43

As a product of its prime factors: 3*7*7 = 147

As a product of its prime factors in exponents: 24*34 = 1296

As a product of its prime factors: 3*7 = 21

75 expressed as a product of its prime factors is 5 squared, and 3.

42 as a product of its prime factors is 2*3*7. 90 as a product of its prime factors is 2*3*3*5.

As a product of its prime factors: 2*29 = 58

The product of the prime factors of 218 is 218. The prime factors of 218 are 2 and 109, making their product 2 x 109 = 218! I wouldn't expect it to be otherwise: the product of the prime factors of a number equal the number.